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A continuous, even periodic function f with period 8 is such that `f(0)=0,f(1)=-2,f(2)=1,f(3)=2,f(4)=3,` then the value of `tan^(-1) tan{f(-5)+f(20)+cos^(-1)(f(-10))+f(17)}` is equal toA. `2pi-3`B. `3-2pi`C. `2pi+3`D. `3-pi` |
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Answer» Correct Answer - D `f(-5)=f(3)=2,f(20)=f(4)=3,f(-10)=f(-2)=f(2)=1`, `f(17)=f(1)=-2` `therefore" "tan^(-1)tan{f(-5)+f(20)+cos^(-1)(f(-10))+f(17)}` `" "=tan^(-1)tan(2+3+0-2)=3-pi`. |
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