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A container of fixed volume filled with an ideal gas which have\(\frac{C_P}{C_V}\) = 1.4, is moving with velocity V' and then suddenly stoped. In this process no heat loss is observed final increase in temperature (M = Molar mass of gas).(1) \(\frac{mv^2}{7R}\) (2) \(\frac{2Mv^2}{7R}\) (3) \(\frac{2Mv^2}{5R}\) (4) \(\frac{Mv^2}{5R}\) |
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Answer» Correct option is (4) \(\frac{Mv^2}{5R}\) For gas \(\frac{C_P}{C_V}=1.4\) \(\cfrac{(\frac f2+1)R}{(\frac f2)}\) = 1.4 ⇒ f = 5 \(\therefore\) \(\triangle\)U = nCv(\(\triangle\)T) Cv = \(\frac f2R\) ΔU is equal to change in internal energy of gas = 1/2 Mv2 So,\(\frac12\)Mv2 = 1 x \(\frac52\)R(ΔT) ΔT = \(\frac{Mv^2}{5R}\) |
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