A constant retarding force of 20N acts on a body of mass 5 kg moving i

1.	A constant retarding force of 20N acts on a body of mass 5 kg moving initially with aspeed of 10 ms How long does the body take to stop?
Answer» ★ Given : CONSTANT retarding force = 20 N Mass of body = 5 kg initial VELOCITY (u) = 10 m/s final velocity (v) = 0 ★ To find : time taken for body to stop. ★ Solution : We know that, F = ma $a = \frac{v - u}{t}$ $F = m \times \frac{v - u}{t}$ by PUTTING the values $- 20 = 5 \times \frac{(0 - 10)}{t}$ $- 20 = \frac{-50}{t}$ by cross multiplication -20 t = -50 $\frac{-50}{-20} = 2.5 \: s$ therefore , time taken = 2.5 seconds..

A constant retarding force of 20N acts on a body of mass 5 kg moving initially with aspeed of 10 ms How long does the body take to stop?

Answer»

CONSTANT retarding force = 20 N

Mass of body = 5 kg

initial VELOCITY (u) = 10 m/s

final velocity (v) = 0

time taken for body to stop.

We know that,

F = ma

$a = \frac{v - u}{t}$

$F = m \times \frac{v - u}{t}$

by PUTTING the values

$- 20 = 5 \times \frac{(0 - 10)}{t}$

$- 20 = \frac{-50}{t}$

by cross multiplication

-20 t = -50

$\frac{-50}{-20} = 2.5 \: s$

therefore , time taken = 2.5 seconds..