1.

A constant force is applied for 2 s on a body of mass 5 kg. As a result, if the velocity of the body is changed from 3 m/s to 7 m/s, find out the value of the applied force.

Answer»

m = 5 kg,

u = 3 m/s,

v = 7 m/s,

t = 2s

a = \(\frac{\text{v}-\text{u}}{t}\)

= \(\frac{7m/s-3m/s}{2s}\)

= 2 m/s2

Force F = ma = 5 kg x 2 m/s2

= 10 kg m/s2

= 10 N



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