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A constant force is applied for 2 s on a body of mass 5 kg. As a result, if the velocity of the body is changed from 3 m/s to 7 m/s, find out the value of the applied force. |
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Answer» m = 5 kg, u = 3 m/s, v = 7 m/s, t = 2s a = \(\frac{\text{v}-\text{u}}{t}\) = \(\frac{7m/s-3m/s}{2s}\) = 2 m/s2 Force F = ma = 5 kg x 2 m/s2 = 10 kg m/s2 = 10 N |
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