A constant force F = m_(2)g//2 is applied on the block of mass m_(1) as shown. The string and the pulley are light and the surface of the table is smooth. Find the acceleration of m_(1).

A constant force F = m_(2)g//2 is applied on the block of mass m_(1) a

1.	A constant force F = m_(2)g//2 is applied on the block of mass m_(1) as shown. The string and the pulley are light and the surface of the table is smooth. Find the acceleration of m_(1).
Answer» `(m_(2)G)/(2m_(1))` `(m_(2)g)/(2(m_(1)+m_(2)))` `(3 m_(2)g)/(2(m_(1)+m_(2)))` `(3m_(2)g)/(2m_(1))` Answer :B