A constant force acts on an object of mass 2kg for 10s and increases i

1.	A constant force acts on an object of mass 2kg for 10s and increases its velocity from 5m/sto 10m/s. Find the magnitude of force applied.
Answer» ANSWER: Step-by-step EXPLANATION: M=2kg= t=10sec u=5m/sec v=10m/sec v=u+at a=(v-u)/t=(10-5)/10=1/2m/sec² F=Ma=2×1/2=1kgm/sec²=1N if this force is applied for 15SEC then, VELOCITY is F=mv/t v=(1×15)/2=7.5m/sec.

A constant force acts on an object of mass 2kg for 10s and increases its velocity from 5m/sto 10m/s. Find the magnitude of force applied.

Answer»

ANSWER:

Step-by-step EXPLANATION:

M=2kg=

t=10sec

u=5m/sec

v=10m/sec

v=u+at

a=(v-u)/t=(10-5)/10=1/2m/sec²

F=Ma=2×1/2=1kgm/sec²=1N

if this force is applied for 15SEC then, VELOCITY is

F=mv/t

v=(1×15)/2=7.5m/sec.

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A constant force acts on an object of mass 2kg for 10s and increases its velocity from 5m/sto 10m/s. Find the magnitude of force applied.​

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A constant force acts on an object of mass 2kg for 10s and increases its velocity from 5m/sto 10m/s. Find the magnitude of force applied.