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A constant force acting in the body of mass 3 kg change its speed from 2m s-1 to 3.5 ms in 25s the direction of motion of the body remains unchanged what is the magnitude and direction of the force |
| Answer» MASS of the BODY, m = 3 kgInitial speed of the body, u = 2 m/sFinal speed of the body, v = 3.5 m/sTime, t = 25 sUsing the first equation of motion, the acceleration (a) produced in the body can be CALCULATED as:v=u+ata=t(v−u) =25(3.5−2)=0.06m/s2As per Newton's second law of motion, FORCE is given as:F=ma =3×0.06=0.18N | |