a constant force act on an object of mass 5 kg for a duration of 2 sec

1.	a constant force act on an object of mass 5 kg for a duration of 2 seconds it increases the objects velocity from 3 metre per second to 7 M per second find the magnitude of the applied force now if the force was applied for a duration of 5 seconds what would be the final velocity of the object explain with video
Answer» FORCE = mass × Acceleration The acceleration = change in VELOCITY ÷ TIME = (7 - 3) ÷ 2 = 2m/s² Force = 5 × 2 = 10N Given INITIAL velocity = 3m/s a = 2m/s² Final velocity in 5 seconds will be : 2 = (V - 3) / 5 10= 5V - 15 25 = 5V V = 5 m/s

a constant force act on an object of mass 5 kg for a duration of 2 seconds it increases the objects velocity from 3 metre per second to 7 M per second find the magnitude of the applied force now if the force was applied for a duration of 5 seconds what would be the final velocity of the object explain with video

Answer»

FORCE = mass × Acceleration

The acceleration = change in VELOCITY ÷ TIME

= (7 - 3) ÷ 2 = 2m/s²

Force = 5 × 2 = 10N

Given INITIAL velocity = 3m/s

a = 2m/s²

Final velocity in 5 seconds will be :

2 = (V - 3) / 5

10= 5V - 15

25 = 5V

V = 5 m/s

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