A conical tent is 10m high and the radius of its base is 24m. Find the

1.	A conical tent is 10m high and the radius of its base is 24m. Find the slant height of the tent. If the cost of 1m2 canvas is ₹ 70, find the cost of canvas required to make the tent.
Answer» It is given that Radius of the conical tent = 24m Height of conical tent = 10m We know that Slant height of conical tent can be written as l = √(r² + h²) By substituting the values l = √(24² + 10²) On further calculation l = √(576 + 100) = √ 676 So we get l = 26m We know that Curved surface area of conical tent = πrl By substituting the values Curved surface area of conical tent = (22/7) × 24 × 26 So we get Curved surface area of conical tent = (13728/7) m² It is given that the cost of 1m²canvas = ₹ 70 So the cost of (13728/7) m² canvas = ₹ 70 × (13728/7) = ₹ 137280 Therefore, the slant height of the tent is 26m and the cost of canvas required to make the tent is ₹ 137280.

A conical tent is 10m high and the radius of its base is 24m. Find the slant height of the tent. If the cost of 1m2 canvas is ₹ 70, find the cost of canvas required to make the tent.

Answer»

It is given that

Radius of the conical tent = 24m

Height of conical tent = 10m

We know that

Slant height of conical tent can be written as

l = √(r² + h²)

By substituting the values

l = √(24² + 10²)

On further calculation

l = √(576 + 100) = √ 676

So we get

l = 26m

We know that

Curved surface area of conical tent = πrl

By substituting the values

Curved surface area of conical tent = (22/7) × 24 × 26

So we get

Curved surface area of conical tent = (13728/7) m²

It is given that the cost of 1m²canvas = ₹ 70

So the cost of (13728/7) m² canvas = ₹ 70 × (13728/7) = ₹ 137280

Therefore, the slant height of the tent is 26m and the cost of canvas required to make the tent is ₹ 137280.