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A conductor of mass `m=5kg` and length `l=4m` is placed on horizontal surface and a uniform magnetic field `B=2` Tesla exist parallel to horizontal surface but perpendicular to the conductor. Suddenly, a certain amount of charge is passed through it, then it is found to jump to a height `h=5m`. Then, find the amount of charge that passes through the conductor in coulomb. (take `g=10m//s^(2)`) |
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Answer» Correct Answer - `00006.25` Impulse, `FDeltat=m sqrt(2gh)` `(ilB)Deltat=msqrt(2gh)`………(i) `iDeltat=Deltaq` `Deltaq=(msqrt(2gh))/(Bl)=(5sqrt(2xx10xx5))/(2xx4)=6.25` Coulomb |
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