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A conductor of axial length 30 cms carries a current of 100 a and lies at right angle to a magnetic field of strength 0.4 tesla. What is the force exerted on it ?

Answer»

ate,◆ Answer-F = 12 N◆ Explaination-# Given-I = 100 AL = 30 cm = 0.3 mB = 0.4 Tθ = 90°# Solution-Force acting on CONDUCTOR in magnetic FIELD is given by-F = IlBsinθSubstitute values-F = 100 × 0.3 × 0.4 × sin90F = 12 NTherefore, force acting on current carrying conductor in given magnetic field is 12 N.Hope it helps...



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