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a conductor is in form of solid rod of outer radius is R and thickness is R/4 .If length of rod is L and resistivity is P then resistance |
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Answer» R=16PL/15πR^2 Explanation: RESISTANCE,R= PL/A and A = πR^2 -πR^2/4 =15πR^2/16 now R = 16PL/15πR^2 |
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