1.

a conductor is in form of solid rod of outer radius is R and thickness is R/4 .If length of rod is L and resistivity is P then resistance ​

Answer»

ANSWER:

R=16PL/15πR^2

Explanation:

RESISTANCE,R= PL/A

and A = πR^2 -πR^2/4

=15πR^2/16

now R = 16PL/15πR^2



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