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A conductivity cell find with 0.1 M KCI gives at `25^(@) C` a resistance of 85.5 other . The conductivity of 0.1 M KCI at `25^(@) C` is 0.01286 `"ohm"^(-1) cm^(-1) `. The same cell filled with 0.005 M HCI gives a resistance of 529 ohms. What is the molar conductivity of HCI solution at `25^(@) C`? |
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Answer» Correct Answer - Molar conductivity of HCI solution . `=^^_(m_((HCI)))` `=416 ohm^(-1) cm^(2) mol^(-1)` Given : Resistance Of KCI solution = `R_(KCI) = 85.5 Omega` Conductivity of KCI solution `= k_(KCI) = 0.01286 ohm^(-1) cm^(-4)` Concentration = C= 0.005 M HCI Resistance of HCI solution = `R _(soln) = 529 ohms ` Molar conductivity of HCI `= ^^_(m(HCI)) = ? ` Conductivity `= (" Cell constant ")/("Resistance ")` `k_(KCI) = ( b) /(R_(KCI))` `:. b =(k_(KCI)) xx R_(KCI) = 0.01286 xx 85.5 = 1.1 cm^(-1)` Conductivity of HCI solution `k_("soln") = ( b )/(R_("soln")) = (1.1)/(529) = 2.08 xx 10^(-3) ohm^(-1) cm^(-1)` Molar conductivity `^^_(m_(HCI)) = .(k_("soln")xx 1000)/(C )` `=(2.08 xx 10^(-3) xx 1000)/(0.005)` `= 416 " ohm"^(-1) cm^(2) mol^(-1)` |
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