A conducting rod of length 1 m and mass 1 kg is suspended by two vertical wires through its ends. An external magnetic field of 2 T is applied perpendicular to rod and plane of arrangement. The current to be passed through the rod to make tension zero is (g = 10 m/s2)

A conducting rod of length 1 m and mass 1 kg is suspended by two verti

1.	A conducting rod of length 1 m and mass 1 kg is suspended by two vertical wires through its ends. An external magnetic field of 2 T is applied perpendicular to rod and plane of arrangement. The current to be passed through the rod to make tension zero is (g = 10 m/s2)
Answer» Explanation:MAGNETIC force on rod = BIℓWeight of the rod = MG. for no tension in the wire, BIℓ = mg∴ I = (mg/Bℓ) = [(1 × 10)/(R × 1)] I = 5AExplanation:PLEASE Mark Me as Brainliest

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A conducting rod of length 1 m and mass 1 kg is suspended by two vertical wires through its ends. An external magnetic field of 2 T is applied perpendicular to rod and plane of arrangement. The current to be passed through the rod to make tension zero is (g = 10 m/s2)

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