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A conducting ring of radius r having charge q is rotating with angular velocity `omega` about its axes. Find the magnetic field at the centre of the ring. |
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Answer» Current in the ring `I=(omegaq)/(2pi)` Magnetic field `B=(mu_0I)/(2r)=(mu_0 omegaq)/((2pi)xx2r)` ` implies B=(mu_0 omegaq)/(4pir)` |
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