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A conducintg circular loop having a redius of 5.0cm, is placed perpendicular to a magnetic field of 0.50 T. It is removed from the field in 0.50 s. Find the average emf produced In the loop during this time. |
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Answer» `epsilon=-(Deltaphi)/(Deltat)=-((phi_(1)-phi_(2)))/(Deltat)` `=(phi_(1)-phi_(2))/(Deltat)` `=(BA-0)/(Deltat)=(0.5xxpi(1xx10^(-2))^(2))/0.5=pixx10^(-4) V` |
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