1.

A condenser of capacity 16mF charged to a potential of 20V is connected to a condenser kf capacity C charged to a potential of 10V as shown in the figure. If the common potential is 14V the capacity C is

Answer»

C1= 16 mF

V1= 20V V2=10V

C2= C

Common potential V=14v

V = C1V1-C2V2/C1+C2

14= 16*20-C*10/16+C

14(16+C)= 16*20-C*10

224+14C= 320- 10C

320-224= 14C+10C

96/24 = C

C= 4 mF



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