A concave mirror produces three times enlarged virtual image of an object placed at 10 cm in front of it. Where is the image located?

A concave mirror produces three times enlarged virtual image of an obj

1.	A concave mirror produces three times enlarged virtual image of an object placed at 10 cm in front of it. Where is the image located?
Answer» = 3 (VIRTUAL image)m = 3 (virtual image)u = - 10 cmm = 3 (virtual image)u = - 10 cmR = ?m = 3 (virtual image)u = - 10 cmR = ?We KNOW thatm = 3 (virtual image)u = - 10 cmR = ?We know thatm = - (v/u)m = 3 (virtual image)u = - 10 cmR = ?We know thatm = - (v/u)3 = -v/(-10)m = 3 (virtual image)u = - 10 cmR = ?We know thatm = - (v/u)3 = -v/(-10)V = 30 cmm = 3 (virtual image)u = - 10 cmR = ?We know thatm = - (v/u)3 = -v/(-10)V = 30 cmAndm = 3 (virtual image)u = - 10 cmR = ?We know thatm = - (v/u)3 = -v/(-10)V = 30 cmAnd1/v + 1/u = 1/fm = 3 (virtual image)u = - 10 cmR = ?We know thatm = - (v/u)3 = -v/(-10)V = 30 cmAnd1/v + 1/u = 1/f1/30 + 1/(-10) = 1/fm = 3 (virtual image)u = - 10 cmR = ?We know thatm = - (v/u)3 = -v/(-10)V = 30 cmAnd1/v + 1/u = 1/f1/30 + 1/(-10) = 1/f-20/300 = 1/fm = 3 (virtual image)u = - 10 cmR = ?We know thatm = - (v/u)3 = -v/(-10)V = 30 cmAnd1/v + 1/u = 1/f1/30 + 1/(-10) = 1/f-20/300 = 1/ff = - 15 cmm = 3 (virtual image)u = - 10 cmR = ?We know thatm = - (v/u)3 = -v/(-10)V = 30 cmAnd1/v + 1/u = 1/f1/30 + 1/(-10) = 1/f-20/300 = 1/ff = - 15 cmRadius of CURVATURE = R = 2fm = 3 (virtual image)u = - 10 cmR = ?We know thatm = - (v/u)3 = -v/(-10)V = 30 cmAnd1/v + 1/u = 1/f1/30 + 1/(-10) = 1/f-20/300 = 1/ff = - 15 cmRadius of curvature = R = 2f= 2 × (-15) = - 30 cmExplanation:plz mark my answer as brainliest.

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A concave mirror produces three times enlarged virtual image of an object placed at 10 cm in front of it. Where is the image located?​

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A concave mirror produces three times enlarged virtual image of an object placed at 10 cm in front of it. Where is the image located?