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a compound on analysis gave the following percentage composition by mass H-9.09, o-36.36, c-54.55. mole mass of compound is 88. Find its molecular Formula? |
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Answer» C8H16O4Explanation: carbon =its percentage 54.55 &its ATOMIC weight 12& relative no of atom= 54.55/12 = 4.53 & it's ratio 4.53/ 2.27=2Hydrogen = its percentage 9.09 and it's Atomic weight 1 &its relative no of atom= 9.09/1=9.09 & its ratio= 9.09/2.27=4oxygen= its percentage 36.36 &its Atomic weight 16 & its relative no of atom= 36.36/16 =2.27 & its ratio = 2.27/2.27=2Empirical formula= C2H4OEmpirical formula weight= 44molecular weight= 2×88=176, n= 176/44=4So, molecular formula= 4 ×empirical formula = 4(C2H4O) = C8H16O4 |
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