A compound on analysis gave the following percentage composition: Na = 14.31%, S = 9.97%, H = 6.22% O = 69.50% Calculate the molecular formula of the compound on the assumption that all the hydrogen in the compound is present in combination with oxygen as water of crystallization. Molecular mass of the compound is 322.

A compound on analysis gave the following percentage composition: Na

1.	A compound on analysis gave the following percentage composition: Na = 14.31%, S = 9.97%, H = 6.22% O = 69.50% Calculate the molecular formula of the compound on the assumption that all the hydrogen in the compound is present in combination with oxygen as water of crystallization. Molecular mass of the compound is 322.
Answer» : NaPercentage composition: 14.31Atomic mass: 23Relative number of atoms: Simplest ratio: Element: SPercentage composition: 9.97Atomic mass: 32Relative number of atoms:Simplest ratio: Element: HPercentage composition: 6.22Atomic mass: 1Relative number of atoms: Simplest ratio: Element: OPercentage composition: 69.5Atomic mass: 16Relative number of atoms: Simplest ratio: The empirical FORMULA = Empirical formula mass = MOLECULAR mass = 322Whole of the hydrogen is present in the form of water. THEREFORE, 10 water MOLECULES are present in the molecule. Therefore, molecular formula =