A compound of metal (M) and nitrogen (N) withformula M,N, contains 28%

1.	A compound of metal (M) and nitrogen (N) withformula M,N, contains 28% of nitrogen. The atomicmass of metal M is(1) 24(2) 972 78(4) 54
Answer» ANSWER: N%=. 1×28×100/M+28 28 = 2800/M+28 M+28=100 M=72

A compound of metal (M) and nitrogen (N) withformula M,N, contains 28% of nitrogen. The atomicmass of metal M is(1) 24(2) 972 78(4) 54

Answer»

N%=. 1×28×100/M+28

28 = 2800/M+28

M+28=100

M=72