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A compound of formula A2B3 has the hcp lattice. Which atom forms the hcp lattice and what fraction of tetrahedral voids is occupied by the other atoms(1) hcp lattice - A, 1/3 Tetrahedral voids - B (2) hcp lattice - A, 2/3 Tetrahedral voids - B (3) hcp lattice - B, 2/3 Tetrahedral voids - A (4) hcp lattice - B, 1/3 Tetrahedral voids - A |
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Answer» The correct option is (4) hcp lattice - B, 1/3 Tetrahedral voids - A Explanation: Let B form hcp lattice no. of B = 6 tetrahedral void occupied by A = 1/3 x 12 = 4 A4B6 or A2B3 |
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