A compound has 20% carbon 46% nitrogen 6.7% hydrogen and rest is zero

1.	A compound has 20% carbon 46% nitrogen 6.7% hydrogen and rest is zero what empirical formula
Answer» Carbon=20/12=1.66 Nitrogen=46/14=3.28 Hydrogen=6.7/1=6 .7 Simple ratio Carbon=1.66/1.66=1 Nitrogen=3.28/1.66=2 Hydrogen=6.7/1.66=4 Empirical formula=C H4 N2 I HOPE this HELPS ( ╹▽╹ )

A compound has 20% carbon 46% nitrogen 6.7% hydrogen and rest is zero what empirical formula

Answer»

Carbon=20/12=1.66

Nitrogen=46/14=3.28

Hydrogen=6.7/1=6 .7

Simple ratio

Carbon=1.66/1.66=1

Nitrogen=3.28/1.66=2

Hydrogen=6.7/1.66=4

Empirical formula=C H4 N2

I HOPE this HELPS ( ╹▽╹ )