A compound contains 4.07% hydrogen, 24.27% carbon and 71.65 % chlorine

1.	A compound contains 4.07% hydrogen, 24.27% carbon and 71.65 % chlorine by mass. Its molar mass is 98.96 g. What is its empirical formula ? Atomic masses of hydrogen, carbon and chlorine are 1.008, 12.000 and 35.453 u, respectively
Answer» Explanation: Divide the given percentages of atoms with their molecular masses H---4.07/1 =4.07 C---24.27/12 =2.02 Cl--71.65/35.5=2.01 step 2 divide all values with the LOWEST VALUE obtained. H---4.07/2.01=2 C---2.02/2.01=1 Cl---2.01/2.01=1 therefore the empirical FORMULA is CH 2 Cl WEIGHT OF EMPIRICAL FORMULA=12+2+35.5=49.5 Given molecular weight =98.96 which is double of empirical weight .therefore molecular formula is C 2 H 4 Cl 2 . BY TEJAS KULKARNI PLEASE FOLLOW AND MARK AS BRAINLIST AND FOLLOW FOR MORE ANSWERS!!

A compound contains 4.07% hydrogen, 24.27% carbon and 71.65 % chlorine by mass. Its molar mass is 98.96 g. What is its empirical formula ? Atomic masses of hydrogen, carbon and chlorine are 1.008, 12.000 and 35.453 u, respectively

Answer»

Explanation:

Divide the given percentages of atoms with their molecular masses

H---4.07/1 =4.07

C---24.27/12 =2.02

Cl--71.65/35.5=2.01

step 2

divide all values with the LOWEST VALUE obtained.

H---4.07/2.01=2

C---2.02/2.01=1

Cl---2.01/2.01=1

therefore the empirical FORMULA is

WEIGHT OF EMPIRICAL FORMULA=12+2+35.5=49.5

Given molecular weight =98.96 which is double of empirical weight .therefore molecular formula is C

BY TEJAS KULKARNI PLEASE FOLLOW AND MARK AS BRAINLIST AND FOLLOW FOR MORE ANSWERS!!