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A composite wire is made by joining two uniform wires. If `l_1 = l_2= l` and ` mu_1 = mu_2 /9 = mu`. Tension in the strings is T , `mu` is mass per unit length. Then lowest frequency such that the junction is an antinode. A. `1/(4l) sqrt(l/(mu))`B. `3/(4l)sqrt(l/(mu))`C. `5/(4l) sqrt(l/(mu))`D. `7/(4l)sqrt(l/(mu))` |
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Answer» Correct Answer - A For antinode `f_(1)=((2n_(1)-1))/(4l)sqrt(l/(mu))` `f_(2)=((2n_(2)-1))/(4l)sqrt(l/(9mu)) =((2n_(2)-1))/(12l)sqrt(l/(mu))` `f=1/(4l)sqrt(l/(mu)) ((2n_(1)-1))/(4l)=(2n_(2)-1)/(12l)` `6n_(1)-3 =2n_(2) -1` `6n_(1)-2n_(2) =2 " " n_(1)=1, n_(2)=2` `3n_(1)-n_(2)=1`, |
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