A Colorless solid `A` liberates a brown gas `B` on acidification, a colorless alkaline gas `(C)`on treatment with `NaOH` and a colorless non-reactive gas `D` on heating. If heating of the solid is continued, it completely disappears. The compound `A` isA. `NH_(4)NO_(2)`B. `PH_(4)NO_(3)`C. `NH_(4)NO_(3)`D. none of these

A Colorless solid `A` liberates a brown gas `B` on acidification, a co

1.	A Colorless solid `A` liberates a brown gas `B` on acidification, a colorless alkaline gas `(C)`on treatment with `NaOH` and a colorless non-reactive gas `D` on heating. If heating of the solid is continued, it completely disappears. The compound `A` isA. `NH_(4)NO_(2)`B. `PH_(4)NO_(3)`C. `NH_(4)NO_(3)`D. none of these
Answer» Correct Answer - A Alkaline gas `C` with `NaOH` indicates that solid should be ammonium salt. Heating the salt, a colorless non-reaching gas `D` is formed. The gas `D` may be nitrogen. The compound may thus be `NH_(4)NO_(2)`. Reactions involved are as follows: `underset (A) (NH_(4))NO_(2) overset(HCl)to NH_(4)Cl+HNO_(2)` `2HNO_(2)toH_(2)O+2NO+[O]` `2NO+2[O]tounderset(B Brown Gas)(2NO_(2))uarr` `NH_(4)NO_(2)+NaOHrarrNaO_(2)+H_(2)O+underset(C)(NH_(3))uarr` C `underset (A) (NH_(4)NO_(2_((s)))) overset ("heat")to underset (D) (N_(2_(("gas"))))uarr+2H_(2)O_(("gas"))uarr` `impliesN_(2)` is a diamagnetic Gas `implies` Bond order of `N_(2)=3`

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