1.

A coll of resistance 10Omegaand inductance 5 H is connected at a 100 V battery. Then the energy stored in the coil is

Answer»

250 J
250 erg
125 J
125 erg

Solution :Here,` R = 10 Omega , L= 5 H, V = 100 V `
` I = V/R = (100 V)/( 10 Omega) = 10 A `
Energy stored = `1/2LI^(2)= 1/2 XX 5(10)^(2)= 250 j`


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