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A coll of resistance 10Omegaand inductance 5 H is connected at a 100 V battery. Then the energy stored in the coil is |
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Answer» 250 J ` I = V/R = (100 V)/( 10 Omega) = 10 A ` Energy stored = `1/2LI^(2)= 1/2 XX 5(10)^(2)= 250 j` |
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