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A coin is places at the bottom of a beaker containing water (refractive index = 4/3) to a depth of 12 cm. By what height the coin appears to be raised when seen from vertically above? |
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Answer» Refractive index of the water, μw = 4/3 Real depth at which the coin is places = 12 cm Shift in the image = ? Shift = real depth × (1 - 1/μ) Shift = 12 × (1 - 3/4) R = 12/4 = 3cm |
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