a coin is placedat the bottom of a beaker containing water(refractive

1.	a coin is placedat the bottom of a beaker containing water(refractive index=4/3) to a depth 12 cm. By what height the coin appears to be raised when seen from vertically above?
Answer» Answer: the height the COIN appears to be raised when seen from vertically above=3cm Explanation: given that, reflective index =4/3 real depth=12cm APPARENT depth=? reflective index =RD/AD 4/3=12/AD AD4=123 AD=123/4 AD=33 AD=9cm now, we have to find the height of the coin appears to be rise when seen from vertically above. =real depth - apparent depth =12 - 9 =3cm I *hope* it *will* *benefit* *you* *buddy. please* *make* my *answer* *BRAINLIEST.*.

a coin is placedat the bottom of a beaker containing water(refractive index=4/3) to a depth 12 cm. By what height the coin appears to be raised when seen from vertically above?

Answer»

Answer:

the height the COIN appears to be raised when seen from vertically above=3cm

Explanation:

given that,

reflective index =4/3

real depth=12cm

APPARENT depth=?

reflective index =RD/AD

4/3=12/AD

AD*4=12*3

AD=12*3/4

AD=3*3

AD=9cm

now,

we have to find the height of the coin appears to be rise when seen from vertically above.

=real depth - apparent depth

=12 - 9 =3cm

I hope it will benefit you buddy.

please make my answer BRAINLIEST..

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a coin is placedat the bottom of a beaker containing water(refractive index=4/3) to a depth 12 cm. By what height the coin appears to be raised when seen from vertically above?​

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a coin is placedat the bottom of a beaker containing water(refractive index=4/3) to a depth 12 cm. By what height the coin appears to be raised when seen from vertically above?