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A coin is placed on a rotating turning table slips if placed at minimum dist of 9cm from centre if angular velocity of turn table is tripled |
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Answer» Explanation: (w= angular VELOCITY) F= m w^2 r F slip= m w^2 40. --> EQN(1) F slip= m (2w)^2 R2 F slip=4m w^2 R2 --> eqn(2) solving 1 and 2 m w^2 40 = 4 m w^2 R2 so R2 = 10 cm |
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