1.

A coil of inductance `300mh` and resistance `2Omega` is connected to a source of voltage `2V`. The current reaches half of its steady state value inA. `0.05 s`B. `0.1 s`C. `0.15 s`D. `0.3 s`

Answer» Correct Answer - B
The current at any instant is given by `l=l_(0)(1-e^(-Rt//L))`
`l_(0)/2=l_(0)(1-e^(-Rt//L))`
`1/2=(1-e^(-Rt//L))`
`e^(-Rt//L)=1/2`
`(Rt)/L=n2`
`therefore t=L/R "ln" 2`
`=(300 xx 10^(-3))/2xx0.693 =150xx0.693xx10^(-3)`
`=0.10395 sec =0.1 sec`


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