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A coil of `Cu` wire (radius `r`, self-inductance `L`) is bent in two concentric turns each having radius `(r )/(2)`. The self-inductance nowA. `2L`B. `L`C. `4L`D. `L//2` |
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Answer» Correct Answer - A ` therefore LpropN^(2)r,`" "`(L_(1))/(L_(2))=(N_(1)/(N_(2)))^(2)xx(r_(1))/(r_(2))` `implies(L)/(L_(2))=((1)/(2))^(2)xx((r)/(r//2))=(1)/(2), L_(2)=2L` |
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