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A coil of cross sectional area 100 `cm^(2)` is placed in the magnetic field, which changes to `4xx10^(-2)Wb//cm^(2)` within 5s. What will be the current across `5Omega` resistance?A. 0.016 AB. 0.16 AC. 1.6 AD. 16.0 A |
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Answer» Correct Answer - B `e=A(dB)/(dt)` `=(100xx10^(-4)xx4xx10^(2))/(5)=0.8V` `I=(e)/(R)=(0.8)/(5)=0.16A` |
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