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A coil of area `500cm^(2)` and having `1000` turns is held perpendicular to a uniform field of `0.4` gauss. The coil is turned through `180^(@)` in `1//10sec` . Calculate the average indued e.m.f. |
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Answer» `A=500cm^(2)=500xxI0^(-4)m^(2)=5xxI0^(-2)m^(2)` `N=I000` , `B=0.4` gauss `=0.4xxI0^(-4)T=4xxI0^(-5)T` `Deltat=(I)/(I0)s` `phi_(I)=NBAcos0=NBA` `phi_(2)NBAcosI80^(@)=-NBA` `|Deltaphi|=2NBA` `|bar(e)|=(|Deltaphi|)/(Deltat)=(2NBA)/(Deltat)=(2xxI000xx4xxI0^(-2))/(I//I0)` `=0.4V` |
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