1.

A coil of area `500cm^(2)` and having `1000` turns is held perpendicular to a uniform field of `0.4` gauss. The coil is turned through `180^(@)` in `1//10sec` . Calculate the average indued e.m.f.

Answer» `A=500cm^(2)=500xxI0^(-4)m^(2)=5xxI0^(-2)m^(2)`
`N=I000` , `B=0.4` gauss `=0.4xxI0^(-4)T=4xxI0^(-5)T`
`Deltat=(I)/(I0)s`
`phi_(I)=NBAcos0=NBA`
`phi_(2)NBAcosI80^(@)=-NBA`
`|Deltaphi|=2NBA`
`|bar(e)|=(|Deltaphi|)/(Deltat)=(2NBA)/(Deltat)=(2xxI000xx4xxI0^(-2))/(I//I0)`
`=0.4V`


Discussion

No Comment Found

Related InterviewSolutions