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A coil of area `0.05 m^(2)` and 500 turns is placed in a magnetic field of strength `4 xx 10^(-5)` tesla. If it is rotated through `90^(@)` in 0.1 sec, then the magnitude of e.m.f. Induced in the coil will beA. 10 mVB. 20 mVC. 5 mVD. 15 mV |
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Answer» Correct Answer - A `e = (d phi)/(dt) = (nAB)/t = (500 xx 5 xx 10^(-2) xx 4 xx 10^(-5))/(10^(-1))` `:. E = 10^(-2) V = 10 mV`. |
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