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A coil of `40 Omega` resistance has `100` turns and radius `6 mm` us connected to ammeter of resistance of `160 ohms`. Coil is placed perpendicular to the magnetic field. When coil is taken out of the field, `32 mu C` charge flows through it. The intensity of magnetic field will beA. 6.55 TB. 5.66 TC. 2.55 TD. 0.566 T |
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Answer» Correct Answer - D We have, `Deltaq=-(N)/(R)Deltaphi and Deltaphi=DeltaB.A cos theta` `therefore" "32xx10^(-6)=-(100)/(160+40)(0-B)xxpixx(6xx10^(-3))^(2)xxcos0^(@)` `therefore` Intensity of magnetic field, `B=0.566T` |
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