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A coil of `40 Omega` resistance has `100` turns and radius `6 mm` us connected to ammeter of resistance of `160 ohms`. Coil is placed perpendicular to the magnetic field. When coil is taken out of the field, `32 mu C` charge flows through it. The intensity of magnetic field will beA. 0.665 TB. 0.656 TC. 0.566 TD. 5.666 T |
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Answer» Correct Answer - C `phi=(phi_(1)-phi_(2))/(R)=(nAB)/(R)` `therefore B=(phiR)/(nA)=0.566T` |
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