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A coil of `40 Omega` resistance has `100` turns and radius `6 mm` us connected to ammeter of resistance of `160 ohms`. Coil is placed perpendicular to the magnetic field. When coil is taken out of the field, `32 mu C` charge flows through it. The intensity of magnetic field will beA. `6.55 T`B. `5.66 T`C. `0.655 T`D. `0.566 T`` |
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Answer» Correct Answer - D `q=(N)/(R )(B_(2)-B_(1))A costheta` `32xx10^(-4)` `=-(100)/((160+40))(0-B)xxpixx(6xx10^(-3))^(2)xxcos0^(@)` `impliesB=0.565T` |
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