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A coil of 0.8 p.f. is connected in series with 110 micro-farad capacitor. Supply frequency is 50 Hz. The potential difference across the coil is found to be equal to that across the capacitor. Calculate the resistance and the inductance of the coil. Calculate the net power factor. |
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Answer» XC = 1/(3.14 × C) = 28.952 ohms ∴ Coil Impedance, Z = 28.952Ω Coil resistance = 28.952 × 0.8 = 23.162 Ω Coil reactance = 17.37 ohms Coil-inductance = 17.37/314 = 55.32 milli-henrys Total impedance, ZT = 23.16 + j 17.37 − j 28.952 = 23.162 − j 11.582 = 25.9 ohms Net power-factor = 23.162/25.9 = 0.8943 leading |
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