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A coil of 0.01 henry inductance and 1 ohm resistance is connected to 200 volt, 50 Hz ac supply. Find the impedance of the circuit and time lag between max. alternating voltage and current. |
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Answer» Here, `L = 0.01 H, R = 1 Omega, E_(v) = 200 V, v = 50 Hz, Z = ?, Delta t = ?` `X_(L) = omega L = 2 pi v L = 2 xx 3.14 xx 50 xx 0.01 = 3.14 Omega` `Z = sqrt(R^(2) + X_(L)^(2)) = sqrt(1^(2) + (3.14)^(2)) = sqrt(10.86) = 3.3 ohm` `tan phi = (omega L)/(R ) = 3.14` `phi = tan^(-1) (3.14) = 72^(@) = 72 xx (pi)/(180) rad` Time lag, `Delta t = (phi)/(omega) = (72 xx pi)/(180 xx 2 pi xx 50) = (1)/(250) sec` |
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