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A coil having an area `2 m^(2)` is placed in a magnetic field which changes from `1 wb//m_(2)` n interval of 2s. The e.m.f. induced in the coil is: |
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Answer» Here, `A = 2 m^(2)`, `(dB)/(dt) = ((4 - 1) Wb//m^(2))/(2 sec) = (3)/(2) T//s` `e = (d phi)/(dt) = A (dB)/(dt) = 2 x (3)/(2) = 3` volt |
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