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A coil having `500` square loops each of side `10 cm` is placed normal to a magnetic flux which increase at the rate of `1.0 "tesla"/"second"`. The induced r.m.f. in volts is |
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Answer» Here, `N = 500, A = 10 xx 10 cm^(2) = 10^(2) xx 10^(4) m^(2)=10^(-2) m^(2)` `(dB)/(dt) = 1.0 T//s, e = ?` `e = N (d phi)/(dt) = N A(dB)/(dt) = 500 xx 10^(-2) xx 1.0 = 5 ` volt |
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