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A coil has a time constant of 1 second and an inductance of 8 H. If the coil is connected to a 100 V d.c. source, determine : (i) the rate of rise of current at the instant of switching (ii) the steady value of the current and (iii) the time taken by the current to reach 60% of the steady value of the current. |
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Answer» λ = L/R ; R = L/λ = 8/1 = 8 ohm (i) Initial di/dt = V/L = 100/8 = 12.5 A/s (ii) IM = V/R = 100/8 = 12.5A (iii) Here, i = 60% of 12.5 = 7.5 A Now, i = Im (1 −e−t/λ) ∴ 7.5 = 12.5 (1 −e−t/1); t = 0.915 second |
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