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A coil has 600 turns which produces `5 xx 10^-3 Wb//turn` of flux when `3 A` current flows in the wire. This produced `6 xx 10^-3` Wb/turn in 1000 turns secondary coil. When the opened, the current drops to zero in `0.2 s` in primary. Find (a) mutual inductance,(b) the induced emf in the secondary,(c) the self-inductance of the primary coil. |
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Answer» a. `M=(N_2phi_2)/i_1=((1000)(6xx10^-23))/3=2H` b. `|e_2|=M((/_i_1)/(/_ ))=((2)(3))/0.2=30V` c. `L_1=(N_1phi_1)/i_1=((600)(5xx10^(-3)))/(3)=1H` |
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