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A coil formed by wrapping 50 turns of wire in the shape of a square is positioned in a magnetic field so that the normal to the plane of the coil makes an angle of `30^@`. with the direction of the field. When the magnetic field is increased uniformly from `200 muT` to `600muT` in `0.4 s`, an emf of magnitude 80.0 mV is induced in the coil. What is the total length of the wire? |
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Answer» Correct Answer - B `e=(N/_phi)/(/_ )=((NS/_B)/(/_ ))cos30^@` `:. S=((e/_ )/(N/_B))sec30^@` `=[((80xx10^-3)(0.4))/((50)(400x10^-6))][2/sqrt3]=1.85m` `:.` Side of square `=1.36m` Total length of wire `=50(4xx1.36)` `=272m` |
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