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A closed container shown in figure is filled with water `(rho=10^(3) kg//M^(3))` This is accelerated in horizonal direction with an acceleration, `a=2m//s^(2)`.Find (a)`p_(C)-p_(D)` and (b) `p_(A)-p_(D)`. |
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Answer» Correct Answer - A::B::D (a) In horizontal direction, pressure decreases in the direction of acceleration. Thus, `p_(C) gt p_(D)` or, `p_(C)-p_(D)=+ rhoax` Substituting the values, we have `p_(C)-p_(D)=(10^(3))(2)(2)` or,`p_(C)-p_(D)=4.0xx10^(3) N//m^(2)` (b) In vertical direction, pressure increses with depth. `:. p_(C) gtp_(A)` or, `p_(A)-p_(C)=-rho gh` `=-(10^(3))(10)(6) (g_(e) =g)` `=-60xx10^(3) N//m^(2)` (b) Now, `p_(A)-p_(D)=(p_(A)-p_(C))+(p_(C)-p_(D))` `=(-60xx10^(3))+(4.0xx10^(3))` `=-56xx10^(3) N//m^(2)` `=-56xx10^(4) N//m^(2)`. |
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