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A clock with an iron pendulum keeps correct time at 20^(@)C. How much will it lose or gain per day if cubical expansion of iron =36xx10^(-6).^(@)C^(-1) . |
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Answer» `Delta T=(Delta L)/(Lalpha)=(5xx10^(-4))/(1xx1.32xx10^(-5))=37.8^(@)C` |
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