1.

A clock with an iron pendulum keeps correct time at 20^(@)C. How much will it lose or gain per day if cubical expansion of iron =36xx10^(-6).^(@)C^(-1) .

Answer»


SOLUTION :`Delta L=L alpha Delta T`
`Delta T=(Delta L)/(Lalpha)=(5xx10^(-4))/(1xx1.32xx10^(-5))=37.8^(@)C`


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