1.

a cistern 6m long and 4 m wide contains water up to a depth of 1 m 25 cm. the total area of the wet surface is:

Answer»
here \: is \: your \: \: answer

↪length = 6m

↪ BREADTH = 4m

so using the formula ,

↪Area of the wet surface,

= [2(lb + bh + LH) - lb] 

= 2(bh + lh) + lb 

= [2 (4 X 1.25 + 6 x 1.25) + 6 x 4]m^2  

= 49m^2.
the \: total \: area \: of \: the \: wet \: surface \: is \: = 49 {m}^{2}


hope \: it \: helps


\beta e \: \beta \gamma \alpha inly


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