A circular thin disc of mass 2 kg has a diameter 0.2 m. Calculate its moment of inertia about an axis passing through the edge and perpendicular to the plane of the disc (in kg m^(2))

A circular thin disc of mass 2 kg has a diameter 0.2 m. Calculate its

1.	A circular thin disc of mass 2 kg has a diameter 0.2 m. Calculate its moment of inertia about an axis passing through the edge and perpendicular to the plane of the disc (in kg m^(2))
Answer» 0.01 0.03 0.02 3 Solution :`I = (MR^(2))/(2)` About axis passing through EDGE , moment of INERTIA = I. `therefore I. = I + MR^(2) ""` (By theorem of PARALLEL axes) or `I. = (MR^2)/(2) + MR^(2) = (3)/(2) MR^(2) = (3)/(2) xx 2 xx (0.1)^(2)` or `I. = 0.03 kg m^(2)`