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a circular loop of radius R is kept in a uniform magnetic field pointing perpendicular into the plane of paper. when a current I flows in the loop, the tension produced in the loop is |
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Answer» mall elementary length dl cut into circle as SHOWN in figure, dθ is the angle subtended by dl into centre of circle . so, elementary length , dl = RdθNow, F = I(dl × B) = Idl.Bsin90° [ because elementary length are PERPENDICULAR upon magnetic field ] = BIRdθAlso tension acts on just OPPOSITE side of FORCE as you can see in figure .So, at equilibrium condition , 2Tsindθ/2 = BIRdθ actually, dθ/2 is very small angle so, sindθ/2 ≈ dθ/2 Hence, 2Tdθ/2 = BIRdθ T = BIR hence tension in the loop is BIR |
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